mariadb/mysql-test/main/key_diff.result
Monty 3fa99f0c0e Change cost for REF to take into account cost for 1 extra key read_next
The main difference in code path between EQ_REF and REF is that for
REF we have to do an extra read_next on the index to check that there
is no more matching rows.

Before this patch we added a preference of EQ_REF by ensuring that REF
would always estimate to find at least 2 rows.

This patch adds the cost of the extra key read_next to REF access and
removes the code that limited REF to at least 2 rows. For some queries
this can have a big effect as the total estimated rows will be halved
for each REF table with 1 rows.

multi_range cost calculations are also changed to take into account
the difference between EQ_REF and REF.

The effect of the patch to the test suite:
- About 80 test case changed
- Almost all changes where for EXPLAIN where estimated rows for REF
  where changed from 2 to 1.
- A few test cases using explain extended had a change of 'filtered'.
  This is because of the estimated rows are now closer to the
  calculated selectivity.
- A very few test had a change of table order.
  This is because the change of estimated rows from 2 to 1 or the small
  cost change for REF
  (main.subselect_sj_jcl6, main.group_by, main.dervied_cond_pushdown,
  main.distinct, main.join_nested, main.order_by, main.join_cache)
- No key statistics and the estimated rows are now smaller which cased
  estimated filtering to be lower.
  (main.subselect_sj_mat)
- The number of total rows are halved.
  (main.derived_cond_pushdown)
- Plans with 1 row changed to use RANGE instead of REF.
  (main.group_min_max)
- ALL changed to REF
  (main.key_diff)
- Key changed from ref + index_only to PRIMARY key for InnoDB, as
  OPTIMIZER_ROW_LOOKUP_COST + OPTIMIZER_ROW_NEXT_FIND_COST is smaller than
  OPTIMIZER_KEY_LOOKUP_COST + OPTIMIZER_KEY_NEXT_FIND_COST.
  (main.join_outer_innodb)
- Cost changes printouts
  (main.opt_trace*)
- Result order change
  (innodb_gis.rtree)
2023-02-10 12:58:50 +02:00

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Text

drop table if exists t1;
CREATE TABLE t1 (
a char(5) NOT NULL,
b char(4) NOT NULL,
KEY (a),
KEY (b)
);
INSERT INTO t1 VALUES ('A','B'),('b','A'),('C','c'),('D','E'),('a','a');
select * from t1,t1 as t2;
a b a b
A B A B
b A A B
C c A B
D E A B
a a A B
A B b A
b A b A
C c b A
D E b A
a a b A
A B C c
b A C c
C c C c
D E C c
a a C c
A B D E
b A D E
C c D E
D E D E
a a D E
A B a a
b A a a
C c a a
D E a a
a a a a
explain select t1.*,t2.* from t1,t1 as t2 where t1.A=t2.B;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL a NULL NULL NULL 5
1 SIMPLE t2 ref b b 4 test.t1.a 1 Using index condition
select t1.*,t2.* from t1,t1 as t2 where t1.A=t2.B order by binary t1.a,t2.a;
a b a b
A B a a
A B b A
C c C c
a a a a
a a b A
b A A B
select * from t1 where a='a';
a b
A B
a a
drop table t1;