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103 lines
2.7 KiB
Text
103 lines
2.7 KiB
Text
drop table if exists t1,t2;
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set @a := foo;
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ERROR 42S22: Unknown column 'foo' in 'field list'
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set @a := connection_id() + 3;
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select @a - connection_id();
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@a - connection_id()
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3
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set @b := 1;
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select @b;
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@b
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1
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CREATE TABLE t1 ( i int not null, v int not null,index (i));
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insert into t1 values (1,1),(1,3),(2,1);
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create table t2 (i int not null, unique (i));
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insert into t2 select distinct i from t1;
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select * from t2;
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i
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1
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2
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select distinct t2.i,@vv1:=if(sv1.i,1,0),@vv2:=if(sv2.i,1,0),@vv3:=if(sv3.i,1,0), @vv1+@vv2+@vv3 from t2 left join t1 as sv1 on sv1.i=t2.i and sv1.v=1 left join t1 as sv2 on sv2.i=t2.i and sv2.v=2 left join t1 as sv3 on sv3.i=t2.i and sv3.v=3;
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i @vv1:=if(sv1.i,1,0) @vv2:=if(sv2.i,1,0) @vv3:=if(sv3.i,1,0) @vv1+@vv2+@vv3
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1 1 0 1 2
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2 1 0 0 1
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explain select * from t1 where i=@vv1;
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id select_type table type possible_keys key key_len ref rows Extra
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1 SIMPLE t1 ref i i 4 const 1 Using where
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explain select * from t1 where @vv1:=@vv1+1 and i=@vv1;
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id select_type table type possible_keys key key_len ref rows Extra
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1 SIMPLE t1 ALL NULL NULL NULL NULL 3 Using where
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explain select @vv1:=i from t1 where i=@vv1;
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id select_type table type possible_keys key key_len ref rows Extra
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1 SIMPLE t1 index NULL i 4 NULL 3 Using where; Using index
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explain select * from t1 where i=@vv1;
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id select_type table type possible_keys key key_len ref rows Extra
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1 SIMPLE t1 ref i i 4 const 1 Using where
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drop table t1,t2;
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set @a=0,@b=0;
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select @a:=10, @b:=1, @a > @b, @a < @b;
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@a:=10 @b:=1 @a > @b @a < @b
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10 1 1 0
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select @a:="10", @b:="1", @a > @b, @a < @b;
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@a:="10" @b:="1" @a > @b @a < @b
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10 1 1 0
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select @a:=10, @b:=2, @a > @b, @a < @b;
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@a:=10 @b:=2 @a > @b @a < @b
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10 2 0 1
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select @a:="10", @b:="2", @a > @b, @a < @b;
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@a:="10" @b:="2" @a > @b @a < @b
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10 2 1 0
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select @a:=1;
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@a:=1
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1
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select @a, @a:=1;
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@a @a:=1
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1 1
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create table t1 (id int, d double, c char(10));
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insert into t1 values (1,2.0, "test");
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select @c:=0;
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@c:=0
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0
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update t1 SET id=(@c:=@c+1);
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select @c;
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@c
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1
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select @c:=0;
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@c:=0
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0
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update t1 set id=(@c:=@c+1);
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select @c;
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@c
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1
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select @c:=0;
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@c:=0
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0
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select @c:=@c+1;
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@c:=@c+1
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1
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select @d,(@d:=id),@d from t1;
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@d (@d:=id) @d
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NULL 1 1
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select @e,(@e:=d),@e from t1;
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@e (@e:=d) @e
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NULL 2 2
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select @f,(@f:=c),@f from t1;
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@f (@f:=c) @f
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NULL test test
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set @g=1;
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select @g,(@g:=c),@g from t1;
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@g (@g:=c) @g
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1 test test
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select @c, @d, @e, @f;
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@c @d @e @f
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1 1 2 test
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select @d:=id, @e:=id, @f:=id, @g:=@id from t1;
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@d:=id @e:=id @f:=id @g:=@id
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1 1 1 NULL
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select @c, @d, @e, @f, @g;
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@c @d @e @f @g
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1 1 1 1 NULL
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drop table t1;
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select @a:=10, @b:=2, @a>@b, @a:="10", @b:="2", @a>@b, @a:=10, @b:=2, @a>@b, @a:="10", @b:="2", @a>@b;
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@a:=10 @b:=2 @a>@b @a:="10" @b:="2" @a>@b @a:=10 @b:=2 @a>@b @a:="10" @b:="2" @a>@b
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10 2 1 10 2 1 10 2 1 10 2 1
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