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1c6b982e02
Users expect window functions to produce a certain ordering of rows in the final result set. Although the standard does not require this, we already have the filesort result done for when we computed the window function. If there is no ORDER BY attached to the query, just keep it till the SELECT is completely evaluated and use that to print the result. Update test cases as many did not take care to guarantee a stable result.
61 lines
1.4 KiB
Text
61 lines
1.4 KiB
Text
--echo #
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--echo # Try DENSE_RANK() function
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--echo #
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create table t1 (
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pk int primary key,
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a int,
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b int
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);
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insert into t1 values
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( 1 , 0, 10),
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( 2 , 0, 10),
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( 3 , 1, 10),
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( 4 , 1, 10),
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( 8 , 2, 10),
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( 5 , 2, 20),
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( 6 , 2, 20),
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( 7 , 2, 20),
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( 9 , 4, 20),
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(10 , 4, 20);
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select a, rank() over (order by a) as rank,
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dense_rank() over (order by a) as dense_rank
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from t1;
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select a, b, rank() over (partition by b order by a) as rank,
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dense_rank() over (partition by b order by a) as dense_rank
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from t1;
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drop table t1;
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--echo #
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--echo # Test with null values in the table.
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--echo #
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create table t2 (s1 int, s2 char(5));
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insert into t2 values (1,'a');
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insert into t2 values (null,null);
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insert into t2 values (1,null);
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insert into t2 values (null,'a');
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insert into t2 values (null,'c');
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insert into t2 values (2,'b');
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insert into t2 values (-1,'');
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select *, rank() over (order by s1) as rank,
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dense_rank() over (order by s1) as dense_rank
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from t2
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order by s1, s2;
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select *, rank() over (partition by s2 order by s1) as rank,
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dense_rank() over (partition by s2 order by s1) as dense_rank
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from t2
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order by s1, s2;
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select *, rank() over (order by s2) as rank,
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dense_rank() over (order by s2) as dense_rank
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from t2
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order by s2, s1;
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select *, rank() over (partition by s1 order by s2) as rank,
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dense_rank() over (partition by s1 order by s2) as dense_rank
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from t2;
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drop table t2;
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