mariadb/mysql-test/t/win_rank.test
Vicențiu Ciorbaru 1c6b982e02 MDEV-12779 Oracle/DB2 Compatibility Implicit Ordering for ROW_NUMBER OVER
Users expect window functions to produce a certain ordering of rows in
the final result set. Although the standard does not require this, we
already have the filesort result done for when we computed the window
function. If there is no ORDER BY attached to the query, just keep it
till the SELECT is completely evaluated and use that to print the
result.

Update test cases as many did not take care to guarantee a stable
result.
2018-11-01 21:15:55 +02:00

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--echo #
--echo # Try DENSE_RANK() function
--echo #
create table t1 (
pk int primary key,
a int,
b int
);
insert into t1 values
( 1 , 0, 10),
( 2 , 0, 10),
( 3 , 1, 10),
( 4 , 1, 10),
( 8 , 2, 10),
( 5 , 2, 20),
( 6 , 2, 20),
( 7 , 2, 20),
( 9 , 4, 20),
(10 , 4, 20);
select a, rank() over (order by a) as rank,
dense_rank() over (order by a) as dense_rank
from t1;
select a, b, rank() over (partition by b order by a) as rank,
dense_rank() over (partition by b order by a) as dense_rank
from t1;
drop table t1;
--echo #
--echo # Test with null values in the table.
--echo #
create table t2 (s1 int, s2 char(5));
insert into t2 values (1,'a');
insert into t2 values (null,null);
insert into t2 values (1,null);
insert into t2 values (null,'a');
insert into t2 values (null,'c');
insert into t2 values (2,'b');
insert into t2 values (-1,'');
select *, rank() over (order by s1) as rank,
dense_rank() over (order by s1) as dense_rank
from t2
order by s1, s2;
select *, rank() over (partition by s2 order by s1) as rank,
dense_rank() over (partition by s2 order by s1) as dense_rank
from t2
order by s1, s2;
select *, rank() over (order by s2) as rank,
dense_rank() over (order by s2) as dense_rank
from t2
order by s2, s1;
select *, rank() over (partition by s1 order by s2) as rank,
dense_rank() over (partition by s1 order by s2) as dense_rank
from t2;
drop table t2;