mariadb/mysql-test/t/having.test

# test of problems with having (Reported by Mark Rogers)
#

--disable_warnings
drop table if exists t1,t2,t3;
--enable_warnings

create table t1 (a int);
select count(a) as b from t1 where a=0 having b > 0;
insert into t1 values (null);
select count(a) as b from t1 where a=0 having b > 0;
select count(a) as b from t1 where a=0 having b >=0;
explain extended select count(a) as b from t1 where a=0 having b >=0;
drop table t1; 

#
# Test of problem with HAVING and AVG()
#

CREATE TABLE t1 (
  raw_id int(10) NOT NULL default '0',
  chr_start int(10) NOT NULL default '0',
  chr_end int(10) NOT NULL default '0',
  raw_start int(10) NOT NULL default '0',
  raw_end int(10) NOT NULL default '0',
  raw_ori int(2) NOT NULL default '0'
);

INSERT INTO t1 VALUES (469713,1,164123,1,164123,1),(317330,164124,317193,101,153170,1),(469434,317194,375620,101,58527,1),(591816,375621,484273,1,108653,1),(591807,484274,534671,91,50488,1),(318885,534672,649362,101,114791,1),(318728,649363,775520,102,126259,1),(336829,775521,813997,101,38577,1),(317740,813998,953227,101,139330,1),(1,813998,953227,101,139330,1);

CREATE TABLE t2 (
  id int(10) unsigned NOT NULL default '0',
  contig_id int(10) unsigned NOT NULL default '0',
  seq_start int(10) NOT NULL default '0',
  seq_end int(10) NOT NULL default '0',
  strand tinyint(2) NOT NULL default '0',
  KEY id (id)
);
INSERT INTO t2 VALUES (133195,469713,61327,61384,1),(133196,469713,64113,64387,1),(133197,1,1,1,0),(133197,1,1,1,-2);
SELECT e.id,
   MIN( IF(sgp.raw_ori=1,
          (e.seq_start+sgp.chr_start-sgp.raw_start),  
          (sgp.chr_start+sgp.raw_end-e.seq_end))) as start, 
   MAX( IF(sgp.raw_ori=1,
           (e.seq_end+sgp.chr_start-sgp.raw_start),  
           (sgp.chr_start+sgp.raw_end-e.seq_start))) as end, 
   AVG(IF (sgp.raw_ori=1,e.strand,(-e.strand))) as chr_strand 
FROM  t1 sgp,
      t2 e  
WHERE sgp.raw_id=e.contig_id 
GROUP BY e.id 
HAVING chr_strand= -1 and end >= 0 
  AND start <= 999660;
drop table t1,t2;

#
# Test problem with having and MAX() IS NOT NULL
#

CREATE TABLE t1 (Fld1 int(11) default NULL,Fld2 int(11) default NULL);
INSERT INTO t1 VALUES (1,10),(1,20),(2,NULL),(2,NULL),(3,50);
select Fld1, max(Fld2) as q from t1 group by Fld1 having q is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having max(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having avg(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having std(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having variance(Fld2) is not null;
drop table t1;

#
# Test problem with count(distinct) in having
#
create table t1 (id int not null, qty int not null);
insert into t1 values (1,2),(1,3),(2,4),(2,5);
select id, sum(qty) as sqty from t1 group by id having sqty>2;
select sum(qty) as sqty from t1 group by id having count(id) > 0;
select sum(qty) as sqty from t1 group by id having count(distinct id) > 0;
drop table t1;

#
# Test case for Bug #4358 Problem with HAVING clause that uses alias from the
#              select list and TEXT field 
#

CREATE TABLE t1 (
  `id` bigint(20) NOT NULL default '0',
  `description` text
) ENGINE=MyISAM;

CREATE TABLE t2 (
  `id` bigint(20) NOT NULL default '0',
  `description` varchar(20)
) ENGINE=MyISAM;

INSERT INTO t1  VALUES (1, 'test');
INSERT INTO t2 VALUES (1, 'test');

CREATE TABLE t3 (
  `id`       bigint(20) NOT NULL default '0',
  `order_id` bigint(20) NOT NULL default '0'
) ENGINE=MyISAM;

select
	a.id, a.description,
	count(b.id) as c 
from t1 a left join t3 b on a.id=b.order_id 
group by a.id, a.description 
having (a.description is not null) and (c=0);

select
	a.*, 
	count(b.id) as c 
from t2 a left join t3 b on a.id=b.order_id 
group by a.id, a.description
having (a.description is not null) and (c=0);

INSERT INTO t1  VALUES (2, 'test2');

select
	a.id, a.description,
	count(b.id) as c 
from t1 a left join t3 b on a.id=b.order_id 
group by a.id, a.description 
having (a.description is not null) and (c=0);
drop table t1,t2,t3;

# End of 4.1 tests

#
# Tests for WL#1972 CORRECT EVALUATION OF COLUMN REFERENCES IN THE HAVING CLAUSE
# Per the SAP VERI tests and WL#1972, MySQL must ensure that HAVING can
# correctly evaluate column references from the GROUP BY clause, even if the
# same references are not also found in the select list.
#

# set global sql_mode='ansi';
# set session sql_mode='ansi';

create table t1 (col1 int, col2 varchar(5), col_t1 int);
create table t2 (col1 int, col2 varchar(5), col_t2 int);
create table t3 (col1 int, col2 varchar(5), col_t3 int);

insert into t1 values(10,'hello',10);
insert into t1 values(20,'hello',20);
insert into t1 values(30,'hello',30);
insert into t1 values(10,'bye',10);
insert into t1 values(10,'sam',10);
insert into t1 values(10,'bob',10);

insert into t2 select * from t1;
insert into t3 select * from t1;

select count(*) from t1 group by col1 having col1 = 10;
select count(*) as count_col1 from t1 group by col1 having col1 = 10;
select count(*) as count_col1 from t1 as tmp1 group by col1 having col1 = 10;
select count(*) from t1 group by col2 having col2 = 'hello';
--error 1054
select count(*) from t1 group by col2 having col1 = 10;
select col1 as count_col1 from t1 as tmp1 group by col1 having col1 = 10;
select col1 as count_col1 from t1 as tmp1 group by col1 having count_col1 = 10;
select col1 as count_col1 from t1 as tmp1 group by count_col1 having col1 = 10;
# ANSI: should return SQLSTATE 42000 Syntax error or access violation 
# MySQL: returns 10 - because of GROUP BY name resolution
select col1 as count_col1 from t1 as tmp1 group by count_col1 having count_col1 = 10;
# ANSI: should return SQLSTATE 42000 Syntax error or access violation 
# MySQL: returns 10 - because of GROUP BY name resolution
select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having col1 = 10;
select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having count_col1 = 10;
select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having col2 = 'hello';
select col1 as count_col1,col2 as group_col2 from t1 as tmp1 group by col1,col2 having group_col2 = 'hello';
--error 1064
select sum(col1) as co12 from t1 group by col2 having col2 10; 
select sum(col1) as co2, count(col2) as cc from t1 group by col1 having col1 =10; 
--error 1054
select t2.col2 from t2 group by t2.col1, t2.col2 having t1.col1 <= 10;


#
# queries with nested sub-queries
#

# the having column is resolved in the same query
select t1.col1 from t1
where t1.col2 in 
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having t2.col1 <= 10);

select t1.col1 from t1
where t1.col2 in 
      (select t2.col2 from t2
       group by t2.col1, t2.col2
       having t2.col1 <=
              (select min(t3.col1) from t3));

# the having column is resolved in the SELECT clause of the outer query -
# works in ANSI
select t1.col1 from t1
where t1.col2 in
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having t1.col1 <= 10);

# the having column is resolved in the SELECT clause of the outer query -
# error in ANSI, works with MySQL extension
select t1.col1 as tmp_col from t1
where t1.col2 in 
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having tmp_col <= 10);

# the having column is resolved in the FROM clause of the outer query -
# works in ANSI
select t1.col1 from t1
where t1.col2 in 
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having col_t1 <= 10);

# Item_field must be resolved in the same way as Item_ref
select sum(col1) from t1
group by col_t1
having (select col_t1 from t2 where col_t1 = col_t2 order by col_t2 limit 1);

# nested queries with HAVING, inner having column resolved in outer FROM clause
# the outer having column is not referenced in GROUP BY which results in an error
--error 1054
select t1.col1 from t1
where t1.col2 in 
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having col_t1 <= 10)
having col_t1 <= 20;

# both having columns are resolved in the GROUP clause of the outer query
select t1.col1 from t1
where t1.col2 in 
      (select t2.col2 from t2 
       group by t2.col1, t2.col2 having col_t1 <= 10)
group by col_t1
having col_t1 <= 20;

#
# nested HAVING clauses
#

# non-correlated subqueries
select col_t1, sum(col1) from t1
group by col_t1
having col_t1 > 10 and
       exists (select sum(t2.col1) from t2
               group by t2.col2 having t2.col2 > 'b');

# correlated subqueries - inner having column 't1.col2' resolves to
# the outer FROM clause, which cannot be used because the outer query
# is grouped
--error 1054
select sum(col1) from t1
group by col_t1
having col_t1 in (select sum(t2.col1) from t2
                  group by t2.col2, t2.col1 having t2.col1 = t1.col1);

# correlated subqueries - inner having column 'col_t1' resolves to
# the outer GROUP clause
select sum(col1) from t1
group by col_t1
having col_t1 in (select sum(t2.col1) from t2
                  group by t2.col2, t2.col1 having t2.col1 = col_t1);

#
# queries with joins and ambiguous column names
#
--error 1052
select t1.col1, t2.col1 from t1, t2 where t1.col1 = t2.col1
group by t1.col1, t2.col1 having col1 = 2;

--error 1052
select t1.col1*10+t2.col1 from t1,t2 where t1.col1=t2.col1
group by t1.col1, t2.col1 having col1 = 2;

drop table t1, t2, t3;

# More queries to test ANSI compatibility
create table t1 (s1 int);
insert into t1 values (1),(2),(3);

select count(*) from t1 group by s1 having s1 is null;

# prepared statements prints warnings too early
--disable_ps_protocol
select s1*0 as s1 from t1 group by s1 having s1 <> 0;
--enable_ps_protocol

# ANSI requires: 3 rows
# MySQL returns: 0 rows - because of GROUP BY name resolution

select s1*0 from t1 group by s1 having s1 = 0;

select s1 from t1 group by 1 having 1 = 0;

select count(s1) from t1 group by s1 having count(1+1)=2;
# ANSI requires: 3 rows
# MySQL returns: 0 rows - because of GROUP BY name resolution

select count(s1) from t1 group by s1 having s1*0=0;

-- error 1052
select * from t1 a, t1 b group by a.s1 having s1 is null;
# ANSI requires: 0 rows
# MySQL returns:
# "ERROR 1052 (23000): Column 's1' in having clause is ambiguous"
# I think the column is ambiguous in ANSI too.
# It is the same as:
#   select a.s1, b.s1 from t1 a, t1 b group by a.s1 having s1 is null;
# currently we first check SELECT, thus s1 is ambiguous.

drop table t1;

create table t1 (s1 char character set latin1 collate latin1_german1_ci);
insert into t1 values ('ü'),('y');

select s1,count(s1) from t1
group by s1 collate latin1_swedish_ci having s1 = 'y';
# ANSI requires: 1 row, with count(s1) = 2
# MySQL returns: 1 row, with count(s1) = 1

drop table t1;