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a843a05f92
mainly occurs on win2003 64bit.
- Execute "exec" commands directly with cmd.exe and replace "--exec echo ..." with "--exec .\echo.exe ..."
client/mysqltest.c:
Workaround the problem with "echo" in windows not behaving like "echo" in Unix.
- Replace "--exec echo ..." with "--exec <path to mysqltest>\echo.exe" thus forcing
use of our own echo implementation which baheves like on Unix.
- The above change makes it possible to remove the need to execute all --exec's
inside cygwin. Add ifdefs to only use use cygwin's bash conditionally
mysql-test/lib/mtr_misc.pl:
Add function for converting to the OS's native format
mysql-test/mysql-test-run.pl:
Convert path to executables to "windows native" (c:\<path>\) instead of "mixed"(c:/<path>) mode
necessary for pipes and redirects to work properly in cmd.exe
client/echo.c:
New BitKeeper file ``client/echo.c''
45 lines
1.4 KiB
C
45 lines
1.4 KiB
C
/* Copyright (C) 2000 MySQL AB
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 2 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program; if not, write to the Free Software
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Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA */
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/*
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echo is a replacement for the "echo" command builtin to cmd.exe
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on Windows, to get a Unix eqvivalent behaviour when running commands
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like:
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$> echo "hello" | mysql
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The windows "echo" would have sent "hello" to mysql while
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Unix echo will send hello without the enclosing hyphens
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This is a very advanced high tech program so take care when
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you change it and remember to valgrind it before production
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use.
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*/
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#include <stdio.h>
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int main(int argc, char **argv)
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{
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int i;
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for (i= 1; i < argc; i++)
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{
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fprintf(stdout, "%s", argv[i]);
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if (i < argc - 1)
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fprintf(stdout, " ");
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}
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fprintf(stdout, "\n");
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return 0;
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}
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