mariadb/mysql-test/r/func_default.result
unknown 02b1eb988d Addition to fix for bug #11314 (test case wasn't complete)
mysql-test/r/func_default.result:
  test result fixed
mysql-test/t/func_default.test:
  test case fixed
2005-06-14 17:50:24 +05:00

23 lines
1.2 KiB
Text

drop table if exists t1,t2;
create table t1(str varchar(10) default 'def',strnull varchar(10),intg int default '10',rel double default '3.14');
insert into t1 values ('','',0,0.0);
select default(str), default(strnull), default(intg), default(rel) from t1;
default(str) default(strnull) default(intg) default(rel)
def NULL 10 3.14
explain extended select default(str), default(strnull), default(intg), default(rel) from t1;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 system NULL NULL NULL NULL 1
Warnings:
Note 1003 select default(`test`.`t1`.`str`) AS `default(str)`,default(`test`.`t1`.`strnull`) AS `default(strnull)`,default(`test`.`t1`.`intg`) AS `default(intg)`,default(`test`.`t1`.`rel`) AS `default(rel)` from `test`.`t1`
select * from t1 where str <> default(str);
str strnull intg rel
0 0
explain select * from t1 where str <> default(str);
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 system NULL NULL NULL NULL 1
drop table t1;
CREATE TABLE t1 (id int(11), s varchar(20));
INSERT INTO t1 VALUES (1, 'one'), (2, 'two'), (3, 'three');
SELECT s, 32 AS mi FROM t1 GROUP BY s HAVING DEFAULT(mi) IS NULL;
ERROR HY000: Field 'mi' doesn't have a default value
DROP TABLE t1;