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- More dbug printouts - More testcases
179 lines
5.6 KiB
Text
179 lines
5.6 KiB
Text
#
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# Table elimination (MWL#17) tests
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#
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--disable_warnings
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drop table if exists t0, t1, t2, t3;
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drop view if exists v1, v2;
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--enable_warnings
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create table t1 (a int);
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insert into t1 values (0),(1),(2),(3);
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create table t0 as select * from t1;
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create table t2 (a int primary key, b int)
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as select a, a as b from t1 where a in (1,2);
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create table t3 (a int primary key, b int)
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as select a, a as b from t1 where a in (1,3);
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--echo # This will be eliminated:
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explain select t1.a from t1 left join t2 on t2.a=t1.a;
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explain extended select t1.a from t1 left join t2 on t2.a=t1.a;
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select t1.a from t1 left join t2 on t2.a=t1.a;
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--echo # This will not be eliminated as t2.b is in in select list:
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explain select * from t1 left join t2 on t2.a=t1.a;
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--echo # This will not be eliminated as t2.b is in in order list:
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explain select t1.a from t1 left join t2 on t2.a=t1.a order by t2.b;
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--echo # This will not be eliminated as t2.b is in group list:
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explain select t1.a from t1 left join t2 on t2.a=t1.a group by t2.b;
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--echo # This will not be eliminated as t2.b is in the WHERE
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explain select t1.a from t1 left join t2 on t2.a=t1.a where t2.b < 3 or t2.b is null;
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--echo # Elimination of multiple tables:
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explain select t1.a from t1 left join (t2 join t3) on t2.a=t1.a and t3.a=t1.a;
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--echo # Elimination of multiple tables (2):
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explain select t1.a from t1 left join (t2 join t3 on t2.b=t3.b) on t2.a=t1.a and t3.a=t1.a;
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--echo # Elimination when done within an outer join nest:
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explain extended
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select t0.*
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from
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t0 left join (t1 left join (t2 join t3 on t2.b=t3.b) on t2.a=t1.a and
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t3.a=t1.a) on t0.a=t1.a;
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--echo # Elimination with aggregate functions
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explain select count(*) from t1 left join t2 on t2.a=t1.a;
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explain select count(1) from t1 left join t2 on t2.a=t1.a;
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explain select count(1) from t1 left join t2 on t2.a=t1.a group by t1.a;
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--echo This must not use elimination:
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explain select count(1) from t1 left join t2 on t2.a=t1.a group by t2.a;
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drop table t0, t1, t2, t3;
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# This will stand for elim_facts
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create table t0 ( id integer, primary key (id));
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# Attribute1, non-versioned
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create table t1 (
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id integer,
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attr1 integer,
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primary key (id),
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key (attr1)
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);
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# Attribute2, time-versioned
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create table t2 (
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id integer,
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attr2 integer,
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fromdate date,
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primary key (id, fromdate),
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key (attr2,fromdate)
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);
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insert into t0 values (0),(1),(2),(3),(4),(5),(6),(7),(8),(9);
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insert into t0 select A.id + 10*B.id from t0 A, t0 B where B.id > 0;
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insert into t1 select id, id from t0;
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insert into t2 select id, id, date_add('2009-06-22', interval id day) from t0;
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insert into t2 select id, id+1, date_add('2008-06-22', interval id day) from t0;
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create view v1 as
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select
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F.id, A1.attr1, A2.attr2
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from
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t0 F
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left join t1 A1 on A1.id=F.id
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left join t2 A2 on A2.id=F.id and
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A2.fromdate=(select MAX(fromdate) from
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t2 where id=A2.id);
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create view v2 as
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select
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F.id, A1.attr1, A2.attr2
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from
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t0 F
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left join t1 A1 on A1.id=F.id
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left join t2 A2 on A2.id=F.id and
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A2.fromdate=(select MAX(fromdate) from
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t2 where id=F.id);
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--echo This should use one table:
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explain select id from v1 where id=2;
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--echo This should use one table:
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explain extended select id from v1 where id in (1,2,3,4);
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--echo This should use facts and A1 tables:
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explain extended select id from v1 where attr1 between 12 and 14;
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--echo This should use facts, A2 and its subquery:
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explain extended select id from v1 where attr2 between 12 and 14;
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# Repeat for v2:
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--echo This should use one table:
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explain select id from v2 where id=2;
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--echo This should use one table:
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explain extended select id from v2 where id in (1,2,3,4);
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--echo This should use facts and A1 tables:
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explain extended select id from v2 where attr1 between 12 and 14;
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--echo This should use facts, A2 and its subquery:
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explain extended select id from v2 where attr2 between 12 and 14;
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drop view v1, v2;
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drop table t0, t1, t2;
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#
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# Tests for the code that uses t.keypartX=func(t.keypartY) equalities to
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# make table elimination inferences
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#
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create table t1 (a int);
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insert into t1 values (0),(1),(2),(3);
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create table t2 (pk1 int, pk2 int, pk3 int, col int, primary key(pk1, pk2, pk3));
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insert into t2 select a,a,a,a from t1;
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--echo This must use only t1:
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explain select t1.* from t1 left join t2 on t2.pk1=t1.a and
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t2.pk2=t2.pk1+1 and
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t2.pk3=t2.pk2+1;
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--echo This must use only t1:
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explain select t1.* from t1 left join t2 on t2.pk1=t1.a and
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t2.pk3=t2.pk1+1 and
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t2.pk2=t2.pk3+1;
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--echo This must use both:
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explain select t1.* from t1 left join t2 on t2.pk1=t1.a and
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t2.pk3=t2.pk1+1 and
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t2.pk2=t2.pk3+t2.col;
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--echo This must use only t1:
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explain select t1.* from t1 left join t2 on t2.pk2=t1.a and
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t2.pk1=t2.pk2+1 and
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t2.pk3=t2.pk1;
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drop table t1, t2;
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#
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# Check that equality propagation is taken into account
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#
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create table t1 (pk int primary key, col int);
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insert into t1 values (1,1),(2,2);
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create table t2 like t1;
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insert into t2 select * from t1;
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create table t3 like t1;
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insert into t3 select * from t1;
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explain
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select t1.* from t1 left join ( t2 left join t3 on t3.pk=t2.col) on t2.col=t1.col;
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explain
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select t1.*, t2.* from t1 left join (t2 left join t3 on t3.pk=t2.col) on t2.pk=t1.col;
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drop table t1, t2;
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