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155 lines
4.8 KiB
C
155 lines
4.8 KiB
C
/* Copyright (c) 2000, 2014, Oracle and/or its affiliates. All rights reserved.
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; version 2 of the License.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program; if not, write to the Free Software
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Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1335 USA */
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/* functions on blocks; Keys and records are saved in blocks */
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#include "heapdef.h"
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/*
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Find record according to record-position.
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The record is located by factoring position number pos into (p_0, p_1, ...)
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such that
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pos = SUM_i(block->level_info[i].records_under_level * p_i)
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{p_0, p_1, ...} serve as indexes to descend the blocks tree.
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*/
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uchar *hp_find_block(HP_BLOCK *block, ulong pos)
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{
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reg1 int i;
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reg3 HP_PTRS *ptr; /* block base ptr */
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for (i=block->levels-1, ptr=block->root ; i > 0 ; i--)
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{
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ptr=(HP_PTRS*)ptr->blocks[pos/block->level_info[i].records_under_level];
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pos%=block->level_info[i].records_under_level;
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}
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return (uchar*) ptr+ pos*block->recbuffer;
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}
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/*
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Get one new block-of-records. Alloc ptr to block if needed
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SYNOPSIS
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hp_get_new_block()
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info heap handle
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block HP_BLOCK tree-like block
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alloc_length OUT Amount of memory allocated from the heap
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Interrupts are stopped to allow ha_panic in interrupts
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RETURN
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0 OK
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1 Out of memory
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*/
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int hp_get_new_block(HP_SHARE *info, HP_BLOCK *block, size_t *alloc_length)
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{
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reg1 uint i,j;
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HP_PTRS *root;
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for (i=0 ; i < block->levels ; i++)
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if (block->level_info[i].free_ptrs_in_block)
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break;
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/*
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Allocate space for leaf block (data) plus space for upper level blocks
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up to first level that has a free slot to put the pointer.
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If this is a new level, we have to allocate pointers to all future
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lower levels.
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For example, for level 0, we allocate data for X rows.
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When level 0 is full, we allocate data for HP_PTRS_IN_NOD + X rows.
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Next time we allocate data for X rows.
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When level 1 is full, we allocate data for HP_PTRS_IN_NOD at level 2 and 1
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+ X rows at level 0.
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*/
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*alloc_length= (sizeof(HP_PTRS) * ((i == block->levels) ? i : i - 1) +
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(ulonglong)block->records_in_block * block->recbuffer);
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if (!(root=(HP_PTRS*) my_malloc(hp_key_memory_HP_PTRS, *alloc_length,
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MYF(MY_WME |
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(info->internal ?
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MY_THREAD_SPECIFIC : 0)))))
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return 1;
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if (i == 0)
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{
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block->levels=1;
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block->root=block->level_info[0].last_blocks=root;
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}
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else
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{
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if ((uint) i == block->levels)
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{
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/* Adding a new level on top of the existing ones. */
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block->levels=i+1;
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/*
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Use first allocated HP_PTRS as a top-level block. Put the current
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block tree into the first slot of a new top-level block.
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*/
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block->level_info[i].free_ptrs_in_block=HP_PTRS_IN_NOD-1;
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((HP_PTRS**) root)[0]= block->root;
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block->root=block->level_info[i].last_blocks= root++;
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}
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/* Occupy the free slot we've found at level i */
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block->level_info[i].last_blocks->
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blocks[HP_PTRS_IN_NOD - block->level_info[i].free_ptrs_in_block--]=
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(uchar*) root;
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/* Add a block subtree with each node having one left-most child */
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for (j=i-1 ; j >0 ; j--)
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{
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block->level_info[j].last_blocks= root++;
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block->level_info[j].last_blocks->blocks[0]=(uchar*) root;
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block->level_info[j].free_ptrs_in_block=HP_PTRS_IN_NOD-1;
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}
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/*
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root now points to last (block->records_in_block* block->recbuffer)
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allocated bytes. Use it as a leaf block.
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*/
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block->level_info[0].last_blocks= root;
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}
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return 0;
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}
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/* free all blocks under level */
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uchar *hp_free_level(HP_BLOCK *block, uint level, HP_PTRS *pos, uchar *last_pos)
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{
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int i,max_pos;
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uchar *next_ptr;
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if (level == 1)
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next_ptr=(uchar*) pos+block->recbuffer;
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else
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{
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max_pos= (block->level_info[level-1].last_blocks == pos) ?
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HP_PTRS_IN_NOD - block->level_info[level-1].free_ptrs_in_block :
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HP_PTRS_IN_NOD;
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next_ptr=(uchar*) (pos+1);
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for (i=0 ; i < max_pos ; i++)
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next_ptr=hp_free_level(block,level-1,
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(HP_PTRS*) pos->blocks[i],next_ptr);
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}
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if ((uchar*) pos != last_pos)
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{
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my_free(pos);
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return last_pos;
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}
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return next_ptr; /* next memory position */
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}
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