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	main.derived_cond_pushdown: Move all 10.3 tests to the end, trim trailing white space, and add an "End of 10.3 tests" marker. Add --sorted_result to tests where the ordering is not deterministic. main.win_percentile: Add --sorted_result to tests where the ordering is no longer deterministic.
		
			
				
	
	
		
			107 lines
		
	
	
	
		
			1.8 KiB
		
	
	
	
		
			Text
		
	
	
	
	
	
			
		
		
	
	
			107 lines
		
	
	
	
		
			1.8 KiB
		
	
	
	
		
			Text
		
	
	
	
	
	
#
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# Try DENSE_RANK() function
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#
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create table t1 (
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pk int primary key,
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a int,
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b int
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);
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insert into t1 values
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( 1 , 0, 10),
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( 2 , 0, 10),
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( 3 , 1, 10),
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( 4 , 1, 10),
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( 8 , 2, 10),
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( 5 , 2, 20),
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( 6 , 2, 20),
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( 7 , 2, 20),
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( 9 , 4, 20),
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(10 , 4, 20);
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select a, rank() over (order by a) as rank,
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dense_rank() over (order by a) as dense_rank
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from t1;
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a	rank	dense_rank
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0	1	1
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0	1	1
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1	3	2
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1	3	2
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2	5	3
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2	5	3
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2	5	3
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2	5	3
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4	9	4
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4	9	4
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select a, b, rank() over (partition by b order by a) as rank,
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dense_rank() over (partition by b order by a) as dense_rank
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from t1;
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a	b	rank	dense_rank
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0	10	1	1
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0	10	1	1
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1	10	3	2
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1	10	3	2
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2	10	5	3
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2	20	1	1
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2	20	1	1
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2	20	1	1
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4	20	4	2
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4	20	4	2
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drop table t1;
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#
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# Test with null values in the table.
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#
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create table t2 (s1 int, s2 char(5));
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insert into t2 values (1,'a');
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insert into t2 values (null,null);
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insert into t2 values (1,null);
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insert into t2 values (null,'a');
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insert into t2 values (null,'c');
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insert into t2 values (2,'b');
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insert into t2 values (-1,'');
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select *, rank() over (order by s1) as rank,
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dense_rank() over (order by s1) as dense_rank
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from t2
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order by s1, s2;
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s1	s2	rank	dense_rank
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NULL	NULL	1	1
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NULL	a	1	1
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NULL	c	1	1
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-1		4	2
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1	NULL	5	3
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1	a	5	3
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2	b	7	4
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select *, rank() over (partition by s2 order by s1) as rank,
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dense_rank() over (partition by s2 order by s1) as dense_rank
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from t2
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order by s1, s2;
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s1	s2	rank	dense_rank
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NULL	NULL	1	1
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NULL	a	1	1
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NULL	c	1	1
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-1		1	1
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1	NULL	2	2
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1	a	2	2
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2	b	1	1
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select *, rank() over (order by s2) as rank,
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dense_rank() over (order by s2) as dense_rank
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from t2
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order by s2, s1;
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s1	s2	rank	dense_rank
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NULL	NULL	1	1
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1	NULL	1	1
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-1		3	2
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NULL	a	4	3
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1	a	4	3
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2	b	6	4
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NULL	c	7	5
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select *, rank() over (partition by s1 order by s2) as rank,
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dense_rank() over (partition by s1 order by s2) as dense_rank
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from t2;
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s1	s2	rank	dense_rank
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NULL	NULL	1	1
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NULL	a	2	2
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NULL	c	3	3
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-1		1	1
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1	NULL	1	1
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1	a	2	2
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2	b	1	1
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drop table t2;
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