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73 lines
2.8 KiB
Text
73 lines
2.8 KiB
Text
###############################################
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# #
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# Prepared Statements test on #
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# "nested sets" representing hierarchies #
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# #
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###############################################
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# Source: http://kris.koehntopp.de/artikel/sql-self-references (dated 1999)
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# Source: http://dbmsmag.com/9603d06.html (dated 1996)
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--disable_warnings
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drop table if exists t1;
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--enable_warnings
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# "Nested Set": This table represents an employee list with a hierarchy tree.
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# The tree is not modeled by "parent" links but rather by showing the "left"
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# and "right" border of any person's "region". By convention, "l" < "r".
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# As it is a tree, these "regions" of two persons A and B are either disjoint,
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# or A's region is completely contained in B's (B.l < A.l < A.r < B.r:
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# B is A's boss), or vice versa.
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# Any other overlaps violate the model. See the references for more info.
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create table t1 (
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id INTEGER AUTO_INCREMENT PRIMARY KEY,
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emp CHAR(10) NOT NULL,
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salary DECIMAL(6,2) NOT NULL,
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l INTEGER NOT NULL,
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r INTEGER NOT NULL);
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prepare st_ins from 'insert into t1 set emp = ?, salary = ?, l = ?, r = ?';
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# Initial employee list:
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# Jerry ( Bert () Chuck ( Donna () Eddie () Fred () ) )
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set @arg_nam= 'Jerry'; set @arg_sal= 1000; set @arg_l= 1; set @arg_r= 12;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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set @arg_nam= 'Bert'; set @arg_sal= 900; set @arg_l= 2; set @arg_r= 3;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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set @arg_nam= 'Chuck'; set @arg_sal= 900; set @arg_l= 4; set @arg_r= 11;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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set @arg_nam= 'Donna'; set @arg_sal= 800; set @arg_l= 5; set @arg_r= 6;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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set @arg_nam= 'Eddie'; set @arg_sal= 700; set @arg_l= 7; set @arg_r= 8;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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set @arg_nam= 'Fred'; set @arg_sal= 600; set @arg_l= 9; set @arg_r= 10;
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execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
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select * from t1;
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# Three successive raises, each one is 100 units for managers, 10 percent for others.
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prepare st_raise_base from 'update t1 set salary = salary * ( 1 + ? ) where r - l = 1';
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prepare st_raise_mgr from 'update t1 set salary = salary + ? where r - l > 1';
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let $1= 3;
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set @arg_percent= .10;
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set @arg_amount= 100;
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while ($1)
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{
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execute st_raise_base using @arg_percent;
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execute st_raise_mgr using @arg_amount;
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dec $1;
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}
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select * from t1;
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# Now, increase salary to a multiple of 50 (checks for bug#6138)
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prepare st_round from 'update t1 set salary = salary + ? - ( salary MOD ? )';
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set @arg_round= 50;
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execute st_round using @arg_round, @arg_round;
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select * from t1;
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drop table t1;
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# End of 4.1 tests
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