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Fixed bug #28571. Outer join queries with ON conditions over

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constant outer tables did not return null complemented
rows when conditions were evaluated to FALSE.
Wrong results were returned because the conditions over constant
outer tables, when being pushed down, were erroneously enclosed 
into the guard function used for WHERE conditions.


mysql-test/r/join_outer.result:
  Added a test case for bug #28571.
mysql-test/t/join_outer.test:
  Added a test case for bug #28571.
sql/sql_select.cc:
  Fixed bug #28571. Outer join queries with ON conditions over
  constant outer tables did not return null complemented
  rows when conditions were evaluated to FALSE.
  Wrong results were returned because the conditions over constant
  outer tables, when being pushed down, were erroneously enclosed 
  into the guard function used for WHERE conditions.
  The problem is fixed in the function make_join_select. Now the
  conditions over constant tables from ON expressions are pushed
  down after the conditions from WHERE has been pushed down.
This commit is contained in:
unknown 2007-05-26 10:33:01 -07:00
commit 90484de3f7
3 changed files with 60 additions and 25 deletions
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15
mysql-test/r/join_outer.result
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@ -1239,3 +1239,18 @@ Handler_read_prev 0
Handler_read_rnd 0
Handler_read_rnd_next 6
DROP TABLE t1,t2;
CREATE TABLE t1 (c int PRIMARY KEY, e int NOT NULL);
INSERT INTO t1 VALUES (1,0), (2,1);
CREATE TABLE t2 (d int PRIMARY KEY);
INSERT INTO t2 VALUES (1), (2), (3);
EXPLAIN SELECT * FROM t1 LEFT JOIN t2 ON e<>0 WHERE c=1 AND d IS NULL;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 const PRIMARY PRIMARY 4 const 1
1 SIMPLE t2 index NULL PRIMARY 4 NULL 3 Using where; Using index; Not exists
SELECT * FROM t1 LEFT JOIN t2 ON e<>0 WHERE c=1 AND d IS NULL;
c e d
1 0 NULL
SELECT * FROM t1 LEFT JOIN t2 ON e<>0 WHERE c=1 AND d<=>NULL;
c e d
1 0 NULL
DROP TABLE t1,t2;