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Fix for bug #1271: Undefined variable in PASSWORD() function is not

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handled correctly
This commit is contained in:
unknown 2003-10-21 15:14:06 +05:00
commit 42de9a3ed9
3 changed files with 20 additions and 1 deletions
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9
mysql-test/t/func_crypt.test
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@ -4,3 +4,12 @@ select length(encrypt('foo', 'ff')) <> 0;
--replace_result $1$aa$4OSUA5cjdx0RUQ08opV27/ aaqPiZY5xR5l.
select old_password('test'), password('test');
select length(encrypt('test')), encrypt('test','aa');
drop table if exists t1;
create table t1 (name varchar(50), pw varchar(16));
insert into t1 values ('tom', password('my_pass'));
set @pass='my_pass';
select name from t1 where name='tom' and pw=password(@pass);
select name from t1 where name='tom' and pw=password(@undefined);
drop table t1;