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Merge lamia.home:/home/timka/mysql/src/5.0-bug-21456
into lamia.home:/home/timka/mysql/src/5.1-bug-21456
This commit is contained in:
commit
0368914b9a
3 changed files with 56 additions and 34 deletions
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@ -563,6 +563,17 @@ id IFNULL(dsc, '-')
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2 line number two
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3 line number three
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drop table t1;
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CREATE TABLE t1 (a int primary key, b int);
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INSERT INTO t1 (a,b) values (1,1), (2,3), (3,2);
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explain SELECT DISTINCT a, b FROM t1 ORDER BY b;
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id select_type table type possible_keys key key_len ref rows Extra
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1 SIMPLE t1 ALL NULL NULL NULL NULL 3 Using filesort
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SELECT DISTINCT a, b FROM t1 ORDER BY b;
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a b
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1 1
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3 2
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2 3
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DROP TABLE t1;
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CREATE TABLE t1 (
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ID int(11) NOT NULL auto_increment,
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x varchar(20) default NULL,
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@ -385,6 +385,17 @@ insert into t1 values (1, "line number one"), (2, "line number two"), (3, "line
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select distinct id, IFNULL(dsc, '-') from t1;
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drop table t1;
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#
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# Bug 21456: SELECT DISTINCT(x) produces incorrect results when using order by
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#
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CREATE TABLE t1 (a int primary key, b int);
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INSERT INTO t1 (a,b) values (1,1), (2,3), (3,2);
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explain SELECT DISTINCT a, b FROM t1 ORDER BY b;
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SELECT DISTINCT a, b FROM t1 ORDER BY b;
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DROP TABLE t1;
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# End of 4.1 tests
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@ -822,6 +822,40 @@ JOIN::optimize()
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if (!order && org_order)
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skip_sort_order= 1;
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}
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/*
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Check if we can optimize away GROUP BY/DISTINCT.
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We can do that if there are no aggregate functions and the
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fields in DISTINCT clause (if present) and/or columns in GROUP BY
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(if present) contain direct references to all key parts of
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an unique index (in whatever order).
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Note that the unique keys for DISTINCT and GROUP BY should not
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be the same (as long as they are unique).
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The FROM clause must contain a single non-constant table.
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*/
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if (tables - const_tables == 1 && (group_list || select_distinct) &&
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!tmp_table_param.sum_func_count &&
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(!join_tab[const_tables].select ||
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!join_tab[const_tables].select->quick ||
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join_tab[const_tables].select->quick->get_type() !=
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QUICK_SELECT_I::QS_TYPE_GROUP_MIN_MAX))
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{
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if (group_list &&
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list_contains_unique_index(join_tab[const_tables].table,
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find_field_in_order_list,
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(void *) group_list))
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{
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group_list= 0;
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group= 0;
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}
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if (select_distinct &&
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list_contains_unique_index(join_tab[const_tables].table,
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find_field_in_item_list,
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(void *) &fields_list))
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{
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select_distinct= 0;
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}
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}
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if (group_list || tmp_table_param.sum_func_count)
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{
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if (! hidden_group_fields && rollup.state == ROLLUP::STATE_NONE)
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@ -891,40 +925,6 @@ JOIN::optimize()
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if (old_group_list && !group_list)
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select_distinct= 0;
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}
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/*
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Check if we can optimize away GROUP BY/DISTINCT.
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We can do that if there are no aggregate functions and the
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fields in DISTINCT clause (if present) and/or columns in GROUP BY
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(if present) contain direct references to all key parts of
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an unique index (in whatever order).
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Note that the unique keys for DISTINCT and GROUP BY should not
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be the same (as long as they are unique).
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The FROM clause must contain a single non-constant table.
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*/
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if (tables - const_tables == 1 && (group_list || select_distinct) &&
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!tmp_table_param.sum_func_count &&
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(!join_tab[const_tables].select ||
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!join_tab[const_tables].select->quick ||
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join_tab[const_tables].select->quick->get_type() !=
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QUICK_SELECT_I::QS_TYPE_GROUP_MIN_MAX))
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{
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if (group_list &&
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list_contains_unique_index(join_tab[const_tables].table,
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find_field_in_order_list,
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(void *) group_list))
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{
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group_list= 0;
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group= 0;
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}
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if (select_distinct &&
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list_contains_unique_index(join_tab[const_tables].table,
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find_field_in_item_list,
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(void *) &fields_list))
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{
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select_distinct= 0;
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}
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}
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if (!group_list && group)
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{
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order=0; // The output has only one row
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