# Below test is valid untill we have True/False implemented as 1/0
# To comply to all rules it must show that: n(AB) = nAonB, n(AoB) = nAnB
select ifnull(A, 'N') as A, ifnull(B, 'N') as B, ifnull(not A, 'N') as nA, ifnull(not B, 'N') as nB, ifnull(A and B, 'N') as AB, ifnull(not (A and B), 'N') as `n(AB)`, ifnull((not A or not B), 'N') as nAonB, ifnull(A or B, 'N') as AoB, ifnull(not(A or B), 'N') as `n(AoB)`, ifnull(not A and not B, 'N') as nAnB from t;
# This should work with any internal representation of True/False
# Result must be same as above
select ifnull(A=1, 'N') as A, ifnull(B=1, 'N') as B, ifnull(not (A=1), 'N') as nA, ifnull(not (B=1), 'N') as nB, ifnull((A=1) and (B=1), 'N') as AB, ifnull(not ((A=1) and (B=1)), 'N') as `n(AB)`, ifnull((not (A=1) or not (B=1)), 'N') as nAonB, ifnull((A=1) or (B=1), 'N') as AoB, ifnull(not((A=1) or (B=1)), 'N') as `n(AoB)`, ifnull(not (A=1) and not (B=1), 'N') as nAnB from t;